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Question Number 68808 by aseer imad last updated on 15/Sep/19
Answered by JDamian last updated on 15/Sep/19
$${I}=\frac{{V}}{{R}}=\frac{\mathrm{10}}{\mathrm{1}+\mathrm{3}+\mathrm{6}}=\mathrm{1}\:{A} \\ $$$$ \\ $$$${E}_{{c}} =\frac{\mathrm{1}}{\mathrm{2}}{CV}^{\mathrm{2}} \\ $$$$ \\ $$$${E}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{10}×\mathrm{10}^{−\mathrm{6}} \:×\:\mathrm{3}^{\mathrm{2}} \:+\:\mathrm{20}×\mathrm{10}^{−\mathrm{6}} ×\mathrm{9}^{\mathrm{2}} \right)= \\ $$$$\:\:\:\:=\:\mathrm{855}×\mathrm{10}^{−\mathrm{6}} \:{J} \\ $$