Find all values for x: (x^2 −7x+11)^(x^2 −13x+42) =1 (Easy)


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Question Number 68935 by Maclaurin Stickker last updated on 17/Sep/19

$F i n d a l l v a l u e s f o r x :$ ${(x^{2} - 7 x + 11)}^{x^{2} - 13 x + 42} = 1$ $(E a s y)$
	Answered by $@ty@m123 last updated on 17/Sep/19

	$x = 7, 6$ $x = 2, 5$ $(C a l c u l a t e d i n m i n d .)$
	Answered by Rasheed.Sindhi last updated on 17/Sep/19

	$E i t h e r b a s e = 1 O r e x p o n e n t = 0$ ${(x^{2} - 7 x + 11)}^{x^{2} - 13 x + 42} = 1$ $x^{2} - 7 x + 11 = 1 ∣ x^{2} - 13 x + 42 = 0$ $x^{2} - 7 x + 10 = 0 ∣ (x - 6) (x - 7) = 0$ $(x - 2) (x - 5) = 0 ∣ x = 6, 7$ $x = 2, 5$
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