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Question Number 68946 by ramirez105 last updated on 17/Sep/19

Commented by kaivan.ahmadi last updated on 17/Sep/19

(∂u/∂x)=(2xy−tany)⇒u(x,y)=x^2 y−xtany+h(y) (∂u/∂y)=x^2 −xsec^2 y=x^2 −xsec^2 y+(dh/dy)⇒(dh/dy)=0⇒h=c′ u(x,y)=c⇒x^2 y−xtany=c

∂u∂x=(2xy−tany)⇒u(x,y)=x2y−xtany+h(y)∂u∂y=x2−xsec2y=x2−xsec2y+dhdy⇒dhdy=0⇒h=c′u(x,y)=c⇒x2y−xtany=c

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