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Question Number 68952 by aliesam last updated on 17/Sep/19

Answered by mind is power last updated on 17/Sep/19

⇒x−1>0⇒x>1 ⇔((x−1)/(x+1))≤((x+1+3)/(x−1))⇒(x−1)^2 ≤(x+4)(x+1) ⇔x^2 −2x+1≤x^2 +5x+1⇔7x≥0⇒x≥0 S=]1,+∞⌊

⇒x−1>0⇒x>1⇔x−1x+1⩽x+1+3x−1⇒(x−1)2⩽(x+4)(x+1)⇔x2−2x+1⩽x2+5x+1⇔7x⩾0⇒x⩾0S=]1,+∞⌊

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