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Question Number 69073 by necxxx last updated on 19/Sep/19

A man wants to shear 17 cars between  his 3 children in the ratio 1:2, 1:3, 1:9  respectively.How will he go about it?

$${A}\:{man}\:{wants}\:{to}\:{shear}\:\mathrm{17}\:{cars}\:{between} \\ $$$${his}\:\mathrm{3}\:{children}\:{in}\:{the}\:{ratio}\:\mathrm{1}:\mathrm{2},\:\mathrm{1}:\mathrm{3},\:\mathrm{1}:\mathrm{9} \\ $$$${respectively}.{How}\:{will}\:{he}\:{go}\:{about}\:{it}? \\ $$

Commented by necxxx last updated on 19/Sep/19

please help

$${please}\:{help} \\ $$

Commented by MJS last updated on 19/Sep/19

this is a very old math joke (1/2)+(1/3)+(1/9)=((17)/(18))  ⇒ he borrows the car of his neighbour  the 1^(st)  child gets 9  the 2^(nd)  child gets 6  the 3^(rd)  child gets 2  finally the neighbour gets his car back

$$\mathrm{this}\:\mathrm{is}\:\mathrm{a}\:\mathrm{very}\:\mathrm{old}\:\mathrm{math}\:\mathrm{joke}\:\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{9}}=\frac{\mathrm{17}}{\mathrm{18}} \\ $$$$\Rightarrow\:\mathrm{he}\:\mathrm{borrows}\:\mathrm{the}\:\mathrm{car}\:\mathrm{of}\:\mathrm{his}\:\mathrm{neighbour} \\ $$$$\mathrm{the}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{child}\:\mathrm{gets}\:\mathrm{9} \\ $$$$\mathrm{the}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{child}\:\mathrm{gets}\:\mathrm{6} \\ $$$$\mathrm{the}\:\mathrm{3}^{\mathrm{rd}} \:\mathrm{child}\:\mathrm{gets}\:\mathrm{2} \\ $$$$\mathrm{finally}\:\mathrm{the}\:\mathrm{neighbour}\:\mathrm{gets}\:\mathrm{his}\:\mathrm{car}\:\mathrm{back} \\ $$

Commented by necxxx last updated on 19/Sep/19

wow...really.

$${wow}...{really}. \\ $$

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