Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 69123 by TawaTawa last updated on 20/Sep/19

Answered by mr W last updated on 20/Sep/19

Commented by mr W last updated on 20/Sep/19

$$A_{ABCD}=bh$$$$A_{AKD}=A$$$$A_{KLCB}=\frac{bH}{2}-(bh-A)=A_{AKD}=A$$$$\Rightarrow \frac{bH}{2}-bh+A=A$$$$\Rightarrow \frac{bH}{2}=bh$$$$\Rightarrow \frac{H}{2}=h$$$$\Rightarrow \frac{H}{h}=2$$$$\frac{H}{h}=\frac{x+5}{x}=2$$$$\Rightarrow x=5$$

Commented by TawaTawa last updated on 20/Sep/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com