Question and Answers Forum

All Questions      Topic List

Mechanics Questions

Previous in All Question      Next in All Question      

Previous in Mechanics      Next in Mechanics      

Question Number 69398 by Tony Lin last updated on 23/Sep/19

Commented by Tony Lin last updated on 23/Sep/19

$$Solve53.\mathrm{\&}55.$$

Answered by mr W last updated on 24/Sep/19

Answered by mr W last updated on 23/Sep/19

Commented by mr W last updated on 24/Sep/19

$$Q55$$$$mg\sin \theta =ma\Rightarrow a=g\sin \theta$$$$N_1=mg\cos \theta$$$$N=Mg+N_1\cos \theta =(M+m{\cos }^2\theta )g$$$$F=N_1\sin \theta =mg\sin \theta \cos \theta$$$$\Rightarrow R=\sqrt{N^2+F^2}=g\sqrt{{(M+m{\cos }^2\theta )}^2+{\left(m\sin \theta \cos \theta \right)}^2}$$$$=g\sqrt{M^2+(2M+m)m{\cos }^2\theta }$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com