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Question Number 69680 by 20190927 last updated on 26/Sep/19
f(x)=xsinx,0<x<π2findf′(x)
Answered by MJS last updated on 26/Sep/19
ddx[uv]=uv(u′vu+v′lnu) ⇒ f′(x)=xsinx(sinxx+cosxlnx)
Commented by20190927 last updated on 26/Sep/19
thankyousomuch
Answered by Henri Boucatchou last updated on 26/Sep/19
f′(x)=(esinxlnx)′=(sinxlnx)′f(x) =(cosxlnx+sinxx)xsinx
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