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Question Number 69878 by jagannath19 last updated on 28/Sep/19
Commented by mr W last updated on 29/Sep/19
(3)I
Commented by jagannath19 last updated on 29/Sep/19
sircanyoupleasetellhow
circularringofmassMandradiusRhastheMoI=IcircularringIcircularring=∫r2dm=R2∫dm=R2M=IMoIofsemi−circularring=IsemiIsemi=∫r2dm=R2∫dm=R2M=IbothringshavethesameMoI.thisiseasytosee:theyhavethesamemassM,theirmasshasthesamedistancetothereferenceaxis,MoIistheproductofmassandsquareofdistance,thereforetheirMoIisthesame.
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