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Question Number 69912 by naka3546 last updated on 29/Sep/19

$$\sqrt{xy}+3=y$$$$Find\frac{dy}{dx}.$$

Answered by MJS last updated on 29/Sep/19

$$\frac{y}{2\sqrt{xy}}dx+\frac{x}{2\sqrt{xy}}dy=dy$$$$\frac{y}{2\sqrt{xy}}dx=(1-\frac{x}{2\sqrt{xy}})dy$$$$\frac{y}{2\sqrt{xy}}dx=\frac{2\sqrt{xy}-x}{2\sqrt{xy}}dy$$$$\frac{dy}{dx}=\frac{y}{2\sqrt{xy}-x}$$

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