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Question Number 70108 by naka3546 last updated on 01/Oct/19

Answered by MJS last updated on 01/Oct/19

$${\left(\frac{1}{4}\right)}^x>3^{36}{\left(\frac{2}{3}\right)}^{18x}$$$$(-2\ln 2)x>36\ln 3+18(\ln 2-\ln 3)x$$$$(18\ln 3-20\ln 2)x>36\ln 3$$$$x>\frac{18\ln 3}{9\ln 3-10\ln 2}\approx 6.68970287$$

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