Question Number 70161 by TawaTawa last updated on 01/Oct/19
Answered by mind is power last updated on 01/Oct/19
$${let}\:{a}=\sqrt{\sqrt{\mathrm{5}}+\mathrm{2}}\:\:{b}=\sqrt{\sqrt{\mathrm{5}}−\mathrm{2}} \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} =\mathrm{2}\sqrt{\mathrm{5}} \\ $$$${ab}=\mathrm{1} \\ $$$$\Rightarrow\left({a}+{b}\right)=\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +\mathrm{2}{ab}}=\sqrt{\mathrm{2}\sqrt{\mathrm{5}}+\mathrm{2}}=\sqrt{\mathrm{2}}.\sqrt{\sqrt{\mathrm{5}}+\mathrm{1}} \\ $$$$\Rightarrow\frac{{a}+{b}}{\sqrt{\sqrt{\mathrm{5}+\mathrm{1}}}}=\sqrt{\mathrm{2}} \\ $$$$\sqrt{\mathrm{3}−\mathrm{2}\sqrt{\mathrm{2}}}=\sqrt{\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{2}} }=\sqrt{\mathrm{2}}−\mathrm{1} \\ $$$${answer}=\mathrm{1} \\ $$$$ \\ $$
Commented by TawaTawa last updated on 01/Oct/19
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$
Commented by mind is power last updated on 01/Oct/19
$${y}'{re}\:{Welcom} \\ $$