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Question Number 70161 by TawaTawa last updated on 01/Oct/19

Answered by mind is power last updated on 01/Oct/19

$$leta=\sqrt{\sqrt{5}+2}b=\sqrt{\sqrt{5}-2}$$$$a^2+b^2=2\sqrt{5}$$$$ab=1$$$$\Rightarrow (a+b)=\sqrt{a^2+b^2+2ab}=\sqrt{2\sqrt{5}+2}=\sqrt{2}.\sqrt{\sqrt{5}+1}$$$$\Rightarrow \frac{a+b}{\sqrt{\sqrt{5+1}}}=\sqrt{2}$$$$\sqrt{3-2\sqrt{2}}=\sqrt{{(\sqrt{2}-1)}^2}=\sqrt{2}-1$$$$answer=1$$$$$$

Commented by TawaTawa last updated on 01/Oct/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by mind is power last updated on 01/Oct/19

$$y^{\prime }reWelcom$$

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