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Question Number 70364 by 20190927 last updated on 03/Oct/19

solve L=lim_(x→0) ((e^x −(1/(1−x)))/x^2 )

$$\mathrm{solve}\:\mathrm{L}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{e}^{\mathrm{x}} −\frac{\mathrm{1}}{\mathrm{1}−\mathrm{x}}}{\mathrm{x}^{\mathrm{2}} } \\ $$

Commented by kaivan.ahmadi last updated on 03/Oct/19

lim_(x→0) (((1−x)e^x −1)/(x^2 (1−x)))=lim_(x→0) ((−xe^x )/(2x−3x^2 ))=  lim_(x→0) ((−e^x −xe^x )/(2−6x))=((−1)/2)

$${lim}_{{x}\rightarrow\mathrm{0}} \frac{\left(\mathrm{1}−{x}\right){e}^{{x}} −\mathrm{1}}{{x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right)}={lim}_{{x}\rightarrow\mathrm{0}} \frac{−{xe}^{{x}} }{\mathrm{2}{x}−\mathrm{3}{x}^{\mathrm{2}} }= \\ $$$${lim}_{{x}\rightarrow\mathrm{0}} \frac{−{e}^{{x}} −{xe}^{{x}} }{\mathrm{2}−\mathrm{6}{x}}=\frac{−\mathrm{1}}{\mathrm{2}} \\ $$

Commented by 20190927 last updated on 03/Oct/19

Thank you

$$\mathrm{Thank}\:\mathrm{you}\: \\ $$

Commented by mathmax by abdo last updated on 03/Oct/19

let f(x)=((e^x −(1/(1−x)))/x^2 ) ⇒f(x) =(((1−x)e^x −1)/(x^2 (1−x)))  we have e^x =1+x +(x^2 /2) +o(x^3 ) ⇒(1−x)e^x  =(1−x)(1+x+(x^2 /2)+o(x^3 ))  =1+x+(x^2 /2)−x−x^2 −(x^3 /2) +o(x^4 )=1−(x^2 /2)−(x^3 /2) +o(x^4 ) ⇒  f(x)∼((−(x^2 /2)−(x^3 /2))/(x^2 (1−x))) ⇒f(x) ∼  ((−(1/2)−(x/2))/(1−x))   (x→0) ⇒  lim_(x→0)    f(x) =−(1/2)

$${let}\:{f}\left({x}\right)=\frac{{e}^{{x}} −\frac{\mathrm{1}}{\mathrm{1}−{x}}}{{x}^{\mathrm{2}} }\:\Rightarrow{f}\left({x}\right)\:=\frac{\left(\mathrm{1}−{x}\right){e}^{{x}} −\mathrm{1}}{{x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right)} \\ $$$${we}\:{have}\:{e}^{{x}} =\mathrm{1}+{x}\:+\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\:+{o}\left({x}^{\mathrm{3}} \right)\:\Rightarrow\left(\mathrm{1}−{x}\right){e}^{{x}} \:=\left(\mathrm{1}−{x}\right)\left(\mathrm{1}+{x}+\frac{{x}^{\mathrm{2}} }{\mathrm{2}}+{o}\left({x}^{\mathrm{3}} \right)\right) \\ $$$$=\mathrm{1}+{x}+\frac{{x}^{\mathrm{2}} }{\mathrm{2}}−{x}−{x}^{\mathrm{2}} −\frac{{x}^{\mathrm{3}} }{\mathrm{2}}\:+{o}\left({x}^{\mathrm{4}} \right)=\mathrm{1}−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}−\frac{{x}^{\mathrm{3}} }{\mathrm{2}}\:+{o}\left({x}^{\mathrm{4}} \right)\:\Rightarrow \\ $$$${f}\left({x}\right)\sim\frac{−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}−\frac{{x}^{\mathrm{3}} }{\mathrm{2}}}{{x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right)}\:\Rightarrow{f}\left({x}\right)\:\sim\:\:\frac{−\frac{\mathrm{1}}{\mathrm{2}}−\frac{{x}}{\mathrm{2}}}{\mathrm{1}−{x}}\:\:\:\left({x}\rightarrow\mathrm{0}\right)\:\Rightarrow \\ $$$${lim}_{{x}\rightarrow\mathrm{0}} \:\:\:{f}\left({x}\right)\:=−\frac{\mathrm{1}}{\mathrm{2}} \\ $$

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