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Question Number 70383 by ®Ëƒ ¬Ë°¹¾¨ ‰¦Í¦¿¨ ¸Ë¹Ç² last updated on 04/Oct/19
IfamatrixAissuchthat3A3+2A2+5A+I=0,thenA−1isequalto
Commented by mathmax by abdo last updated on 04/Oct/19
3A3+2A2+5A+I=0⇒3A3+2A2+5A=−I⇒A.(−3A2−2A−5I)=I⇒A−1=−3A2−2A−5I.
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