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Question Number 70653 by naka3546 last updated on 06/Oct/19
limx→π2(sinx−cosx)tanx=...
Commented by kaivan.ahmadi last updated on 06/Oct/19
limx→π2(sinx−cosx−1)tanx=limx→π2(sin2x−sinx−tanx)=−∞⇒limx→π2(sinx−cosx)tanx=e−∞=0
Answered by sadimuhmud 136 last updated on 06/Oct/19
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