Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 70768 by abdusalamyussif@gmail.com last updated on 07/Oct/19

Commented by abdusalamyussif@gmail.com last updated on 07/Oct/19

$$\mathrm{thanks}\mathrm{so}\mathrm{much}\mathrm{sir}$$

Answered by MJS last updated on 07/Oct/19

$$\frac{m{(m^2+1)}^{\frac{1}{2}}-2m^2{(m^2+1)}^{-\frac{1}{2}}}{{(m^2+1)}^{-1}}=$$$$=m(m^2+1)({(m^2+1)}^{\frac{1}{2}}-\frac{2m}{{(m^2+1)}^{\frac{1}{2}}})=$$$$=m{(m^2+1)}^{\frac{1}{2}}(m^2+1-2m)=$$$$=m{(m^2+1)}^{\frac{1}{2}}{(m-1)}^2=$$$$=m{(m-1)}^2\sqrt{m^2+1}$$

Commented by abdusalamyussif@gmail.com last updated on 07/Oct/19

$$\mathrm{thanks}\mathrm{so}\mathrm{much}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com