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Question Number 70798 by jagannath19 last updated on 08/Oct/19
Commented by jagannath19 last updated on 08/Oct/19
withexplanationpleasesir
Answered by mind is power last updated on 08/Oct/19
v=dxdtletsfindequagionofv(x)v(x)=ax+blinea=8−00−4=−2v(0)=b=8⇒v(x)=−2x+8⇒dxdt=−2x+8a=dvdt=ddt(−2x+8)=−2dxdt=−2v⇒a(x)=−2v(x)a(x)=−2(−2x+8)=4x−16a(0)=−16a(4)=0⇒draw(2)answer
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