Question and Answers Forum

All Questions      Topic List

Mechanics Questions

Previous in All Question      Next in All Question      

Previous in Mechanics      Next in Mechanics      

Question Number 71053 by jagannath19 last updated on 11/Oct/19

Commented by jagannath19 last updated on 11/Oct/19

$$explain$$

Answered by mr W last updated on 11/Oct/19

$$letV=speedontheground$$$$\frac{1}{2}{mV}^2=mgH+\frac{1}{2}{mv}^2$$$$\Rightarrow V=\sqrt{2gH+v^2}$$$$Visindependentfromthedirection$$$$\Rightarrow \left(4\right)iscorrect$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com