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Question Number 71172 by aliesam last updated on 12/Oct/19

$$findfherange$$$$$$$$f\left(x\right)=\frac{4}{1+\sqrt{x}}$$

Commented by kaivan.ahmadi last updated on 12/Oct/19

$$\sqrt{x}⩾0\Rightarrow 1+\sqrt{x}⩾1\Rightarrow \frac{4}{1+\sqrt{x}}⩽4$$$$but\frac{4}{1+\sqrt{x}}>0$$$$\Rightarrow 0<\frac{4}{1+\sqrt{x}}⩽4$$$$\Rightarrow R_f=(0,4]$$

Commented by aliesam last updated on 12/Oct/19

$$thankyousir$$

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