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Question Number 7126 by Tawakalitu. last updated on 11/Aug/16

Commented by Tawakalitu. last updated on 11/Aug/16

I need solution to this one. thanks in advance

$${I}\:{need}\:{solution}\:{to}\:{this}\:{one}.\:{thanks}\:{in}\:{advance} \\ $$

Commented by Yozzii last updated on 13/Aug/16

u_(n+1) =(√(2+u_n ))  u_0 =0⇒u_1 =(√2)  ⇒u_2 =(√(2+(√2)))  ⇒u_3 =(√(2+(√(2+(√2)))))  u_(n+1) ^2 −u_n −2=0  −−−−−−−−−−−−−−−−−−−  (Under construction)

$${u}_{{n}+\mathrm{1}} =\sqrt{\mathrm{2}+{u}_{{n}} } \\ $$$${u}_{\mathrm{0}} =\mathrm{0}\Rightarrow{u}_{\mathrm{1}} =\sqrt{\mathrm{2}} \\ $$$$\Rightarrow{u}_{\mathrm{2}} =\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}} \\ $$$$\Rightarrow{u}_{\mathrm{3}} =\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}}} \\ $$$${u}_{{n}+\mathrm{1}} ^{\mathrm{2}} −{u}_{{n}} −\mathrm{2}=\mathrm{0} \\ $$$$−−−−−−−−−−−−−−−−−−− \\ $$$$\left({Under}\:{construction}\right) \\ $$$$ \\ $$$$ \\ $$

Commented by Tawakalitu. last updated on 13/Aug/16

Thank you for your time sir.

$${Thank}\:{you}\:{for}\:{your}\:{time}\:{sir}. \\ $$

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