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Question Number 71371 by rajesh4661kumar@gmail.com last updated on 14/Oct/19

Commented by prakash jain last updated on 15/Oct/19

x^2 +y^2 −2x+2y−23=0 (x−1)^2 +(y+1)^2 =25 center(1,−1) radius=5 let tanget be x+2y+c=0 distance from center to tangent ∣((1−2+c)/(√5))∣=5 (((c−1)/(√5)))^2 =25 (c−1)^2 =25×5 c−1=±5(√5) c=1±5(√5)

x2+y2−2x+2y−23=0(x−1)2+(y+1)2=25center(1,−1)radius=5lettangetbex+2y+c=0distancefromcentertotangent∣1−2+c5∣=5(c−15)2=25(c−1)2=25×5c−1=±55c=1±55

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