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Question Number 71533 by pete last updated on 16/Oct/19

$$\mathrm{Three}\mathrm{interior}\mathrm{angles}\mathrm{of}\mathrm{a}\mathrm{nonagon}\mathrm{are}$$$$\mathrm{equal}\mathrm{and}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{the}\mathrm{other}\mathrm{six}\mathrm{is}1050°$$$$\mathrm{Find}\mathrm{the}\mathrm{size}\mathrm{of}\mathrm{one}\mathrm{of}\mathrm{the}\mathrm{equal}\mathrm{angles}.$$

Answered by MJS last updated on 17/Oct/19

$$\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{the}\mathrm{interior}\mathrm{angles}\mathrm{is}1260°$$$$\frac{1260°-1050°}{3}=70°$$

Commented by pete last updated on 18/Oct/19

$$\mathrm{Thanks}\mathrm{very}\mathrm{much}\mathrm{sir}$$

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