Question and Answers Forum

All Questions      Topic List

Differentiation Questions

Previous in All Question      Next in All Question      

Previous in Differentiation      Next in Differentiation      

Question Number 71550 by mhmd last updated on 17/Oct/19

Answered by MJS last updated on 17/Oct/19

it′ wrong, it must be (((n+1)),(k) ) = ((n),(k) ) + ((n),((k−1)) ) ((n),(k) ) + ((n),((k−1)) ) =((n!)/(k!(n−k)!))+((n!)/((k−1)!(n−k+1)!))= =((n!(n−k+1))/((k−1)!(n−k+1)!k))+((n!k)/((k−1)!(n−k+1)!k))= =((n!(n−k+1)+n!k)/((k−1)!(n−k+1)!k))=((n!(n+1))/(k!(n+1−k)!))= =(((n+1)!)/(k!(n+1−k)!))= (((n+1)),(k) )

it′wrong,itmustbe(n+1k)=(nk)+(nk−1)(nk)+(nk−1)=n!k!(n−k)!+n!(k−1)!(n−k+1)!==n!(n−k+1)(k−1)!(n−k+1)!k+n!k(k−1)!(n−k+1)!k==n!(n−k+1)+n!k(k−1)!(n−k+1)!k=n!(n+1)k!(n+1−k)!==(n+1)!k!(n+1−k)!=(n+1k)

Terms of Service

Privacy Policy

Contact: info@tinkutara.com