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Question Number 71831 by ahmadshahhimat775@gmail.com last updated on 20/Oct/19

Commented by kaivan.ahmadi last updated on 20/Oct/19

hi mr ahmadi  where are you from?

$${hi}\:{mr}\:{ahmadi} \\ $$$${where}\:{are}\:{you}\:{from}? \\ $$

Commented by Abdo msup. last updated on 21/Oct/19

let decompose F(x)=(1/(Π_(k=0) ^m (x+k)))  F(x) =Σ_(k=0) ^m  (a_k /(x+k))  a_k =lim_(x→−k)   (x+k)F(x)  =lim_(x→−k)    (1/(x(x+1)...(x+k−1)(x+k+1)...(x+m)))  =(1/((−k)(−k+1)....(−k+k−1)(−k+k+1)...(−k+m)))  =(1/((−1)^k k!(m−k)!)) =(((−1)^k )/(k!(m−k)!)) =(1/(m!))(−1)^k  C_m ^k  ⇒  F(x)=(1/(m!))Σ_(k=0) ^m  (((−1)^k  C_m ^k )/(x+k)) ⇒  ∫    (dx/(x(x+1)....(x+m))) =(1/(m!))Σ_(k=0) ^m (−1)^k  C_m ^k ln∣x+k∣ +C

$${let}\:{decompose}\:{F}\left({x}\right)=\frac{\mathrm{1}}{\prod_{{k}=\mathrm{0}} ^{{m}} \left({x}+{k}\right)} \\ $$$${F}\left({x}\right)\:=\sum_{{k}=\mathrm{0}} ^{{m}} \:\frac{{a}_{{k}} }{{x}+{k}} \\ $$$${a}_{{k}} ={lim}_{{x}\rightarrow−{k}} \:\:\left({x}+{k}\right){F}\left({x}\right) \\ $$$$={lim}_{{x}\rightarrow−{k}} \:\:\:\frac{\mathrm{1}}{{x}\left({x}+\mathrm{1}\right)...\left({x}+{k}−\mathrm{1}\right)\left({x}+{k}+\mathrm{1}\right)...\left({x}+{m}\right)} \\ $$$$=\frac{\mathrm{1}}{\left(−{k}\right)\left(−{k}+\mathrm{1}\right)....\left(−{k}+{k}−\mathrm{1}\right)\left(−{k}+{k}+\mathrm{1}\right)...\left(−{k}+{m}\right)} \\ $$$$=\frac{\mathrm{1}}{\left(−\mathrm{1}\right)^{{k}} {k}!\left({m}−{k}\right)!}\:=\frac{\left(−\mathrm{1}\right)^{{k}} }{{k}!\left({m}−{k}\right)!}\:=\frac{\mathrm{1}}{{m}!}\left(−\mathrm{1}\right)^{{k}} \:{C}_{{m}} ^{{k}} \:\Rightarrow \\ $$$${F}\left({x}\right)=\frac{\mathrm{1}}{{m}!}\sum_{{k}=\mathrm{0}} ^{{m}} \:\frac{\left(−\mathrm{1}\right)^{{k}} \:{C}_{{m}} ^{{k}} }{{x}+{k}}\:\Rightarrow \\ $$$$\int\:\:\:\:\frac{{dx}}{{x}\left({x}+\mathrm{1}\right)....\left({x}+{m}\right)}\:=\frac{\mathrm{1}}{{m}!}\sum_{{k}=\mathrm{0}} ^{{m}} \left(−\mathrm{1}\right)^{{k}} \:{C}_{{m}} ^{{k}} {ln}\mid{x}+{k}\mid\:+{C} \\ $$$$ \\ $$$$ \\ $$

Answered by MJS last updated on 20/Oct/19

=Σ_(n=0) ^m [(m−n)!n!cos (nπ) ×ln (x+n)]+C

$$=\underset{{n}=\mathrm{0}} {\overset{{m}} {\sum}}\left[\left({m}−{n}\right)!{n}!\mathrm{cos}\:\left({n}\pi\right)\:×\mathrm{ln}\:\left({x}+{n}\right)\right]+{C} \\ $$

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