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Question Number 7189 by Tawakalitu. last updated on 15/Aug/16

Evaluate   :   Σ ((sin(n))/n)  ,   From   1 to  infinity.

$${Evaluate}\:\:\::\:\:\:\Sigma\:\frac{{sin}\left({n}\right)}{{n}}\:\:,\:\:\:{From}\:\:\:\mathrm{1}\:{to}\:\:{infinity}. \\ $$

Commented by Yozzia last updated on 15/Aug/16

f(x)=(a_0 /2)+Σ_(n=1) ^∞ {a_n cos((nπx)/L)+b_n sin((nπx)/L)}  Fourier series with a_n =0, b_n =(1/n), x=1  and L=π ?

$${f}\left({x}\right)=\frac{{a}_{\mathrm{0}} }{\mathrm{2}}+\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left\{{a}_{{n}} {cos}\frac{{n}\pi{x}}{{L}}+{b}_{{n}} {sin}\frac{{n}\pi{x}}{{L}}\right\} \\ $$$${Fourier}\:{series}\:{with}\:{a}_{{n}} =\mathrm{0},\:{b}_{{n}} =\frac{\mathrm{1}}{{n}},\:{x}=\mathrm{1} \\ $$$${and}\:{L}=\pi\:? \\ $$

Commented by Tawakalitu. last updated on 15/Aug/16

Yes sir the sin is 3n ..... i have change it. Thank you sir.

$${Yes}\:{sir}\:{the}\:{sin}\:{is}\:\mathrm{3}{n}\:.....\:{i}\:{have}\:{change}\:{it}.\:{Thank}\:{you}\:{sir}. \\ $$

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