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Question Number 71894 by 20190927 last updated on 21/Oct/19
limx→π2(sinx)tanx
Commented by kaivan.ahmadi last updated on 21/Oct/19
=elimx→π2(sinx−1)tanx=elimx→π2sinx−1cotx=elimx→π2cosx−(1+cot2x)=e0=1
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