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Question Number 71925 by Henri Boucatchou last updated on 22/Oct/19

$$\mathit{S}\mathit{o}\mathit{l}\mathit{v}\mathit{e}\sqrt{1-{\mathit{x}}^2}={\mathit{x}}^{4/3}$$

Answered by MJS last updated on 23/Oct/19

$$x=t^{3/2}$$$$\sqrt{1-t^3}=t^2$$$$1-t^3=t^4$$$$t^4+t^3-1=0$$$$\mathrm{no}\mathrm{useful}\mathrm{exact}\mathrm{solution}$$$$t\approx .819173$$$$\Rightarrow x=\pm .741418$$

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