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Question Number 71983 by device4438043516@gmail.com last updated on 23/May/20

$$ \\ $$

Answered by Henri Boucatchou last updated on 23/Oct/19

d(e^(vlnu) ) = u^v  d(vlnu)                     = u^v  (lnu dv + v(du/u))

$$\boldsymbol{{d}}\left(\boldsymbol{{e}}^{\boldsymbol{{vlnu}}} \right)\:=\:\boldsymbol{{u}}^{\boldsymbol{{v}}} \:\boldsymbol{{d}}\left(\boldsymbol{{vlnu}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\boldsymbol{{u}}^{\boldsymbol{{v}}} \:\left(\boldsymbol{{lnu}}\:\boldsymbol{{dv}}\:+\:\boldsymbol{{v}}\frac{\boldsymbol{{du}}}{\boldsymbol{{u}}}\right) \\ $$

Commented by Henri Boucatchou last updated on 23/Oct/19

Thank′s, you′re welcome

$$\boldsymbol{{Thank}}'\boldsymbol{{s}},\:\boldsymbol{{you}}'\boldsymbol{{re}}\:\boldsymbol{{welcome}} \\ $$

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