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Question Number 71993 by TawaTawa last updated on 23/Oct/19

Answered by mind is power last updated on 23/Oct/19

let∠ AC^ E=∠ADE=x  ⇒∠ECD=3x−x=2x⇒EC=ED  ECD isocel Triangl  ∠ADC=∠EDC−∠EDA=2x−x=x  △ADE=AD.ED.((sin(x))/2)  △ACE=((AC.CEsin(x))/2)  ((△ADE)/(△ACE))=((AD.DEsin(x))/(AC.CE.sin(x)))=((AD)/(AC))   {≪ED=EC≫}  we have In ADE  ((AD)/(sin(3x)))=((AC)/(sin(x)))  ⇒((AD)/(AC))=((sin(3x))/(sin(x)))=((△ADE)/(△ACE))  lim_(x→0) ((sin(3x))/(sin(x)))=lim_(x→0) ((3.sin(3x))/(3x)).(((sin(x))/x))^(−1)   lim ((sint)/t)=1⇒lim_(x→0)  ((3sin(3x))/(3x)).(((sin(x))/x))^(−1) =3  we can also  use sin(3x)=−4sin^3 (x)+3sin(x)  ⇒((sin(3x))/(sin(x)))=−4sin^2 (x)+3→3

letACE=ADE=xECD=3xx=2xEC=EDECDisocelTrianglADC=EDCEDA=2xx=xADE=AD.ED.sin(x)2ACE=AC.CEsin(x)2ADEACE=AD.DEsin(x)AC.CE.sin(x)=ADAC{ED=EC}wehaveInADEADsin(3x)=ACsin(x)ADAC=sin(3x)sin(x)=ADEACElimx0sin(3x)sin(x)=limx03.sin(3x)3x.(sin(x)x)1limsintt=1limx03sin(3x)3x.(sin(x)x)1=3wecanalsousesin(3x)=4sin3(x)+3sin(x)sin(3x)sin(x)=4sin2(x)+33

Commented by TawaTawa last updated on 23/Oct/19

God bless you sir, thanks for your time

Godblessyousir,thanksforyourtime

Commented by mind is power last updated on 23/Oct/19

happy this help you sir have a nice day

happythishelpyousirhaveaniceday

Commented by TawaTawa last updated on 23/Oct/19

Yes sir,  help me look at question  71761

Yessir,helpmelookatquestion71761

Commented by mind is power last updated on 24/Oct/19

3002!!=[2003] ?

3002!!=[2003]?

Commented by TawaTawa last updated on 24/Oct/19

No sir

Nosir

Commented by TawaTawa last updated on 24/Oct/19

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