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Question Number 72247 by TawaTawa last updated on 26/Oct/19

Answered by mind is power last updated on 26/Oct/19

s_1 =s_2 =s  ((TS)/(PR))=((QT)/(QP))⇒TS=((41)/3)  a=∠QST ,r=∠QST=∠PRQ  ((SQ)/(sin(a)))=((14)/(sin(R)))  ((28)/(sin(s)))=((ps)/(sin(a)))  ((PS)/(sin(R)))=((41)/(sin(s)))⇒41sin(r)=28sin(a)  ((SQ)/(sin(a)))=((14)/(sin(r)))⇒SQ=((14sin(r))/(sin(a)))=14((28)/(41))=((392)/(41))

s1=s2=sTSPR=QTQPTS=413a=QST,r=QST=PRQSQsin(a)=14sin(R)28sin(s)=pssin(a)PSsin(R)=41sin(s)41sin(r)=28sin(a)SQsin(a)=14sin(r)SQ=14sin(r)sin(a)=142841=39241

Commented by TawaTawa last updated on 27/Oct/19

God bless you sir. I appreciate

Godblessyousir.Iappreciate

Commented by mind is power last updated on 27/Oct/19

y,re welcom

y,rewelcom

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