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Question Number 72414 by aliesam last updated on 28/Oct/19

Commented by aliesam last updated on 28/Oct/19

$$a,banddarecentresofthreecircles$$$$find$$$$\frac{AC}{AB}$$

Answered by mr W last updated on 28/Oct/19

$$letAC=a,AB=BD=b$$$$a\sin 30°=b\sin 60°$$$$\frac{AC}{AB}=\frac{a}{b}=\frac{\sin 60°}{\sin 30°}=\sqrt{3}$$

Commented by aliesam last updated on 28/Oct/19

$$godblessyousir$$

Commented by mr W last updated on 28/Oct/19

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