Question Number 72443 by masoomashujayee678@gmail.com last updated on 28/Oct/19
![2[0.5{48−31}^2 +35]=?](Q72443.png)
$$\mathrm{2}\left[\mathrm{0}.\mathrm{5}\left\{\mathrm{48}−\mathrm{31}\right\}^{\mathrm{2}} +\mathrm{35}\right]=? \\ $$
Answered by behi83417@gmail.com last updated on 28/Oct/19
![=2×.5×[48−31]^2 +2×35= =[48−31]^2 +70=17^2 +70= =289+70=359 .](Q72444.png)
$$=\mathrm{2}×.\mathrm{5}×\left[\mathrm{48}−\mathrm{31}\right]^{\mathrm{2}} +\mathrm{2}×\mathrm{35}= \\ $$$$=\left[\mathrm{48}−\mathrm{31}\right]^{\mathrm{2}} +\mathrm{70}=\mathrm{17}^{\mathrm{2}} +\mathrm{70}= \\ $$$$=\mathrm{289}+\mathrm{70}=\mathrm{359}\:\:\:. \\ $$