(α+β)^2 = α^2 + 2αβ + β^(2 )


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Question Number 72595 by zillnehu@gmail.com last updated on 30/Oct/19

${(α + β)}^{2} = α^{2} + 2 α β + β^{2}$
Commented by ajfour last updated on 30/Oct/19

$a c c o r d i n g t o n e w r e s e a r c h . .$
Commented by MJS last updated on 30/Oct/19

$one day we might even find that 1 + 1 = 2$
Commented by Learner-123 last updated on 30/Oct/19
if we replace, beta by -beta we may discover one more equation which will say 1-1=0 ��
	Answered by Tanmay chaudhury last updated on 30/Oct/19

	Commented by Tanmay chaudhury last updated on 30/Oct/19

	${(a + b)}^{2} = s u m o f a r e a o f t w o s q u a r e t h a t i s$ $a^{2} + b^{2} a n d s u m o f a r e a o f t w o r e c t a n g l e t h a t$ $i s a b + a b s o$ $a n s w e r i s a^{2} + b^{2} + a b + a b$ $= a^{2} + 2 a b + b^{2}$
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