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Question Number 72724 by rajesh4661kumar@gmail.com last updated on 01/Nov/19

Commented by kaivan.ahmadi last updated on 01/Nov/19

(π/2)<x_1 <x_2 <π⇒0<∣cosx_2 ∣<∣cosx_1 ∣<1⇒  log∣cosx_2 ∣<log∣cosx_1 ∣

$$\frac{\pi}{\mathrm{2}}<{x}_{\mathrm{1}} <{x}_{\mathrm{2}} <\pi\Rightarrow\mathrm{0}<\mid{cosx}_{\mathrm{2}} \mid<\mid{cosx}_{\mathrm{1}} \mid<\mathrm{1}\Rightarrow \\ $$$${log}\mid{cosx}_{\mathrm{2}} \mid<{log}\mid{cosx}_{\mathrm{1}} \mid \\ $$$$ \\ $$$$ \\ $$

Commented by Henri Boucatchou last updated on 02/Nov/19

You  would  have  first  correct  the  interval before...

$${You}\:\:{would}\:\:{have}\:\:{first}\:\:{correct}\:\:{the}\:\:{interval}\:{before}... \\ $$

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