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Question Number 72838 by Rio Michael last updated on 03/Nov/19

$$giventhatf\left(x\right)=\frac{\mid x-2\mid }{1-\mid x\mid }$$$$checkiffiscontinuousax=2$$$$hencewritef\left(x\right)asapairwisefunction$$

Commented by mathmax by abdo last updated on 03/Nov/19

$$f\left(2\right)=0and{lim}_{x\to 2^{+}}f\left(x\right)={lim}_{x\to 2^{+}}\frac{x-2}{1-2}=0$$$${lim}_{x\to 2^{-}}f\left(x\right)={lim}_{x\to 2^{-}}\frac{-x+2}{1-2}=0$$$${lim}_{x\to 2^{-}}f\left(x\right)={lim}_{x\to 2^{+}}f\left(x\right)=f\left(2\right)\Rightarrow fiscontinueat{x}_0=2$$

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