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Question Number 72871 by TawaTawa last updated on 04/Nov/19

Answered by ajfour last updated on 04/Nov/19

Commented by ajfour last updated on 04/Nov/19

$$Topvertexoftriangle$$$$Q(\frac{a}{2},\frac{a\sqrt{3}}{2})$$$$slopeofline$$$$\frac{\frac{a\sqrt{3}}{2}}{\frac{a}{2}-x}=\frac{\frac{a\sqrt{3}}{2}+a}{\frac{a}{2}-y}$$$$\Rightarrow \frac{a}{2}-y=\frac{2}{a\sqrt{3}}(\frac{a\sqrt{3}}{2}+a)(\frac{a}{2}-x)$$$$y=\frac{a}{2}-(1+\frac{2}{\sqrt{3}})(\frac{a}{2}-x)$$

Commented by TawaTawa last updated on 04/Nov/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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