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Question Number 72883 by mhmd last updated on 04/Nov/19
ifw=f(uandv)wherefuu+fvv=0andu=(x2−y2)/2andv=xyshowthatwxx+wyy=0?pleassirhelpme
Answered by mind is power last updated on 04/Nov/19
w(x,y)=f(u,v)w(x,y)=f(β(x,y))⇒jacW=jac(f).jacβ(x,y)⇒(∂w∂x,∂w∂y)=(∂f∂u,∂f∂v).[x−yyx]⇒∂w∂x=x∂f∂u+y∂f∂v⇒∂w∂y=−y∂f∂u+x∂f∂v∂2W∂x2=∂f∂u+x(∂2f∂u2.x+∂2f∂u∂vy)+y(∂2f∂v∂ux+∂2f∂v2y)∂2w∂y2=−∂f∂u−y(∂2f∂u2.−y+∂2f∂u∂vx)+x(∂2f∂u∂v.−y+∂2f∂v2.x)⇒∂2w∂x2=∂f∂u+2xy∂2f∂u∂v+x2∂2f∂u2+y2∂2f∂v2∂2w∂y2=−∂f∂u−2xy∂2f∂u∂v+x2∂2f∂v2+y2∂2f∂u2⇒∂2w∂x2+∂2w∂y2=(x2+y2)[∂2f∂u2+∂2f∂v2]=(x2+y2).0=0
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