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Question Number 73111 by oyemi kemewari last updated on 06/Nov/19

Answered by mr W last updated on 07/Nov/19

5=(1/2)gt^2   ⇒t=10 s  horizontal distance =0.8×10=8 m

$$\mathrm{5}=\frac{\mathrm{1}}{\mathrm{2}}{gt}^{\mathrm{2}} \\ $$$$\Rightarrow{t}=\mathrm{10}\:{s} \\ $$$${horizontal}\:{distance}\:=\mathrm{0}.\mathrm{8}×\mathrm{10}=\mathrm{8}\:{m}\: \\ $$

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