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Question Number 73222 by Tanmay chaudhury last updated on 08/Nov/19

	Answered by Tanmay chaudhury last updated on 08/Nov/19

	$[\vec{a} \vec{b} \vec{c}] = 2 = (\vec{a} \times \vec{b}) . \vec{c}$ $l (\vec{b} \times \vec{c}) . \vec{c} + m (\vec{c} \times \vec{a}) . \vec{c} + n (\vec{a} \times \vec{b}) . \vec{c} = 4 i . \vec{c}$ $l \times 0 + m \times 0 + n [a b c] = 4 i . ({i c}_{x} + {j c}_{y} + {k c}_{z}) = 4 c_{x}$ $2 n = 4 c_{x} s i m i l a r l y 2 l = 4 a_{x} 2 m = 4 b_{x}$ $i (a_{x} + b_{x} + c_{x}) = 3 i \to a_{x} + b_{x} + c_{x} = 3$ $2 (l + m + n) = 4 (a_{x} + b_{x} + c_{x}) = 4 \times 3$ $l + m + n = 6$ $p l z c h e c k$
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