Question and Answers Forum

All Questions      Topic List

Mechanics Questions

Previous in All Question      Next in All Question      

Previous in Mechanics      Next in Mechanics      

Question Number 73260 by Lontum Hans last updated on 09/Nov/19

Answered by mr W last updated on 09/Nov/19

$$T_{max}=m(\frac{v^2}{r}+g)=8(\frac{6^2}{2}+10)=224N$$$$T_{min}=m(\frac{v^2}{r}-g)=8(\frac{6^2}{2}-10)=64N$$

Commented by Lontum Hans last updated on 09/Nov/19

$$\mathrm{nN}otaccurate$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com