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Question Number 73279 by byaw last updated on 09/Nov/19

Answered by mr W last updated on 09/Nov/19

$$40=v_0\times 4+\frac{1}{2}a\times 4^2$$$$\Rightarrow 10=v_0+2a...\left(i\right)$$$$72=v_0\times 6+\frac{1}{2}a\times 6^2$$$$\Rightarrow 12=v_0+3a...\left(ii\right)$$$$\left(ii\right)-\left(i\right):$$$$a=2m/s^2$$$$$$$$from\left(i\right):$$$$v_0=10-2\times 2=6m/s$$$$$$$$v_{t=10}=6+2\times 10=26m/s$$$$$$$$v_{s=600}=\sqrt{v_0^2+2as}=\sqrt{6^2+2\times 2\times 600}=2\sqrt{609}$$$$=49.36m/s$$

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