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Question Number 73358 by 07032041818 last updated on 10/Nov/19

$$1/4x2-1/2x-13=0$$

Commented by MJS last updated on 10/Nov/19

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{not}\mathrm{clear}\mathrm{whether}\mathrm{you}\mathrm{mean}$$$$\frac{1}{4}{x}^2-\frac{1}{2}x-13=0$$$$\mathrm{in}\mathrm{this}\mathrm{case}\times 4$$$$x^2-2x-52=0$$$$x=1\pm \sqrt{53}$$$$\mathrm{or}\mathrm{you}\mathrm{mean}$$$$\frac{1}{4x^2}-\frac{1}{2x}-13=0$$$$\mathrm{in}\mathrm{this}\mathrm{case}\times (-4x^2)/52$$$$x^2+\frac{1}{26}x-\frac{1}{52}=0$$$$x=-\frac{1}{52}\pm \frac{\sqrt{53}}{52}$$

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