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Question Number 73441 by Learner-123 last updated on 12/Nov/19

Answered by mr W last updated on 12/Nov/19

((1+2)/1)=(((7+d)/7))^2   ⇒d=7((√3)−1)=5.12 m    v_0 t=7  1=(1/2)gt^2  ⇒t=(1/(√5))  v_0 =7(√5)=15.65 m/s

1+21=(7+d7)2d=7(31)=5.12mv0t=71=12gt2t=15v0=75=15.65m/s

Commented by Learner-123 last updated on 12/Nov/19

how comes the 1^(st)  line?

howcomesthe1stline?

Commented by mr W last updated on 12/Nov/19

Commented by mr W last updated on 12/Nov/19

parabola:  y=Ax^2   y_1 =Ax_1 ^2   y_2 =Ax_2 ^2   ⇒(y_2 /y_1 )=((x_2 /x_1 ))^2

parabola:y=Ax2y1=Ax12y2=Ax22y2y1=(x2x1)2

Commented by Learner-123 last updated on 13/Nov/19

thanks sir.

thankssir.

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