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Question Number 73523 by 01 last updated on 13/Nov/19

$$\mathrm{prove}\mathrm{that}:$$ $$2^{\pi }>8$$

Answered by MJS last updated on 13/Nov/19

$$3<\pi \Rightarrow \pi =3+p;p>0$$ $$2^{3+p}>2^3$$ $$2^3{2}^p>2^3$$ $$2^p>1$$ $$p\ln 2>0$$ $$p>0$$ $$\mathrm{true}$$

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