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Question Number 73561 by Rio Michael last updated on 13/Nov/19

$$findthevalueof\lambda forwhich$$ $$f:x\to \{\begin{array}{l}2\lambda -x,ifx<1\\ {\lambda }^2+x-1,ifx>1\end{array}$$ $$hasalimitasx\to 1$$

Answered by ajfour last updated on 13/Nov/19

$$2\lambda -1={\lambda }^2$$ $$\lambda =1.$$

Commented byRio Michael last updated on 13/Nov/19

$$thankssir$$

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