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Question Number 73712 by FCB last updated on 15/Nov/19

Answered by MJS last updated on 15/Nov/19

$$\underset{x\to 0^{-}}{\lim }\frac{1}{x}=-\mathrm{\infty }$$$$\underset{x\to 0^{+}}{\lim }\frac{1}{x}=+\mathrm{\infty }$$$$\Rightarrow \underset{x\to 0}{\lim }\frac{1}{x}{\mathrm{doesn}}^{\prime }\mathrm{t}\mathrm{exist}$$

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