Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 73817 by Rio Michael last updated on 16/Nov/19

find the solutions of the equation  in  0 ≤ θ ≤ π    sin2θ = secθ

$${find}\:{the}\:{solutions}\:{of}\:{the}\:{equation} \\ $$$${in}\:\:\mathrm{0}\:\leqslant\:\theta\:\leqslant\:\pi \\ $$$$\:\:{sin}\mathrm{2}\theta\:=\:{sec}\theta \\ $$

Answered by mr W last updated on 16/Nov/19

sin 2θ≤1  sec θ≥1  sin 2θ=1 ⇒θ=(π/4)  sec θ=1 ⇒θ=0  ⇒no solution for θ such that sin 2θ=1 and sec θ=1!

$$\mathrm{sin}\:\mathrm{2}\theta\leqslant\mathrm{1} \\ $$$$\mathrm{sec}\:\theta\geqslant\mathrm{1} \\ $$$$\mathrm{sin}\:\mathrm{2}\theta=\mathrm{1}\:\Rightarrow\theta=\frac{\pi}{\mathrm{4}} \\ $$$$\mathrm{sec}\:\theta=\mathrm{1}\:\Rightarrow\theta=\mathrm{0} \\ $$$$\Rightarrow{no}\:{solution}\:{for}\:\theta\:{such}\:{that}\:\mathrm{sin}\:\mathrm{2}\theta=\mathrm{1}\:{and}\:\mathrm{sec}\:\theta=\mathrm{1}! \\ $$

Commented by Rio Michael last updated on 16/Nov/19

thanks

$${thanks} \\ $$

Commented by peter frank last updated on 16/Nov/19

thank you

$${thank}\:{you} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com