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Question Number 73817 by Rio Michael last updated on 16/Nov/19

find the solutions of the equation  in  0 ≤ θ ≤ π    sin2θ = secθ

findthesolutionsoftheequationin0θπsin2θ=secθ

Answered by mr W last updated on 16/Nov/19

sin 2θ≤1  sec θ≥1  sin 2θ=1 ⇒θ=(π/4)  sec θ=1 ⇒θ=0  ⇒no solution for θ such that sin 2θ=1 and sec θ=1!

sin2θ1secθ1sin2θ=1θ=π4secθ=1θ=0nosolutionforθsuchthatsin2θ=1andsecθ=1!

Commented by Rio Michael last updated on 16/Nov/19

thanks

thanks

Commented by peter frank last updated on 16/Nov/19

thank you

thankyou

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