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Question Number 73896 by liki last updated on 16/Nov/19

Commented by liki last updated on 16/Nov/19

$$...Anyonetoassistme..$$

Answered by mr W last updated on 16/Nov/19

$$10-x=y-10$$$$\Rightarrow x+y-20=0$$$$\frac{x}{1}=\frac{y}{x}$$$$\Rightarrow y=x^2$$$$\Rightarrow x^2+x-20=0$$$$\Rightarrow (x+5)(x-4)=0$$$$\Rightarrow x=-5or4$$$$\Rightarrow y=25or16$$

Commented by liki last updated on 16/Nov/19

$$..thankssir..$$

Answered by $@ty@m123 last updated on 16/Nov/19

$$10-x=y-10$$$$\Rightarrow x+y=20...\left(1\right)$$$$\frac{x}{1}=\frac{y}{x}$$$$\Rightarrow x^2=y.....\left(2\right)$$$$From\left(1\right)\mathrm{\&}\left(2\right)$$$$x^2+x-20=0$$$$x=\frac{-1\pm \sqrt{1+80}}{2}=\frac{-1\pm 9}{2}=4,-5$$$$\Rightarrow y=16,25$$

Commented by liki last updated on 16/Nov/19

$$....Thanksalotsir..$$

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