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Question Number 73896 by liki last updated on 16/Nov/19

Commented by liki last updated on 16/Nov/19

...Anyone to assist me..

$$...{Anyone}\:{to}\:{assist}\:{me}.. \\ $$

Answered by mr W last updated on 16/Nov/19

10−x=y−10  ⇒x+y−20=0  (x/1)=(y/x)  ⇒y=x^2   ⇒x^2 +x−20=0  ⇒(x+5)(x−4)=0  ⇒x=−5 or 4  ⇒y=25 or 16

$$\mathrm{10}−{x}={y}−\mathrm{10} \\ $$$$\Rightarrow{x}+{y}−\mathrm{20}=\mathrm{0} \\ $$$$\frac{{x}}{\mathrm{1}}=\frac{{y}}{{x}} \\ $$$$\Rightarrow{y}={x}^{\mathrm{2}} \\ $$$$\Rightarrow{x}^{\mathrm{2}} +{x}−\mathrm{20}=\mathrm{0} \\ $$$$\Rightarrow\left({x}+\mathrm{5}\right)\left({x}−\mathrm{4}\right)=\mathrm{0} \\ $$$$\Rightarrow{x}=−\mathrm{5}\:{or}\:\mathrm{4} \\ $$$$\Rightarrow{y}=\mathrm{25}\:{or}\:\mathrm{16} \\ $$

Commented by liki last updated on 16/Nov/19

..thanks sir..

$$..{thanks}\:{sir}.. \\ $$

Answered by $@ty@m123 last updated on 16/Nov/19

10−x=y−10  ⇒x+y=20 ...(1)  (x/1)=(y/x)  ⇒x^2 =y  .....(2)  From (1) &(2)  x^2 +x−20=0  x=((−1±(√(1+80)))/2) =((−1±9)/2) =4,−5  ⇒y=16, 25

$$\mathrm{10}−{x}={y}−\mathrm{10} \\ $$$$\Rightarrow{x}+{y}=\mathrm{20}\:...\left(\mathrm{1}\right) \\ $$$$\frac{{x}}{\mathrm{1}}=\frac{{y}}{{x}} \\ $$$$\Rightarrow{x}^{\mathrm{2}} ={y}\:\:.....\left(\mathrm{2}\right) \\ $$$${From}\:\left(\mathrm{1}\right)\:\&\left(\mathrm{2}\right) \\ $$$${x}^{\mathrm{2}} +{x}−\mathrm{20}=\mathrm{0} \\ $$$${x}=\frac{−\mathrm{1}\pm\sqrt{\mathrm{1}+\mathrm{80}}}{\mathrm{2}}\:=\frac{−\mathrm{1}\pm\mathrm{9}}{\mathrm{2}}\:=\mathrm{4},−\mathrm{5} \\ $$$$\Rightarrow{y}=\mathrm{16},\:\mathrm{25} \\ $$

Commented by liki last updated on 16/Nov/19

....Thanks alot sir..

$$....{Thanks}\:{alot}\:{sir}.. \\ $$

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