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Question Number 73910 by Rio Michael last updated on 16/Nov/19

Commented by Rio Michael last updated on 16/Nov/19

given figure 1. in which direction will the reaction of at the hinge be inclined. is it to the vertical or horizontal?

$${given}\:{figure}\:\mathrm{1}. \\ $$$${in}\:{which}\:{direction}\:{will}\:{the}\:{reaction}\:{of}\:{at}\:{the} \\ $$$${hinge}\:{be}\:{inclined}. \\ $$$${is}\:{it}\:{to}\:{the}\:{vertical}\:{or}\:{horizontal}? \\ $$$$ \\ $$

Commented by mr W last updated on 16/Nov/19

Commented by Rio Michael last updated on 16/Nov/19

thanks sir,where do i place the angle θ for the Reaction at the hinge

$${thanks}\:{sir},{where}\:{do}\:{i}\:{place}\:{the}\:{angle}\:\theta\:{for}\:{the}\: \\ $$$${Reaction}\:{at}\:{the}\:{hinge} \\ $$

Commented by mr W last updated on 16/Nov/19

tan θ=(((L/4)×tan 40°)/L)=((tan 40°)/4) ⇒θ=tan^(−1) (((tan 40°)/4))=11.85°

$$\mathrm{tan}\:\theta=\frac{\frac{{L}}{\mathrm{4}}×\mathrm{tan}\:\mathrm{40}°}{{L}}=\frac{\mathrm{tan}\:\mathrm{40}°}{\mathrm{4}} \\ $$$$\Rightarrow\theta=\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{tan}\:\mathrm{40}°}{\mathrm{4}}\right)=\mathrm{11}.\mathrm{85}° \\ $$

Commented by mr W last updated on 16/Nov/19

Commented by Rio Michael last updated on 16/Nov/19

thank you sir

$${thank}\:{you}\:{sir} \\ $$

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