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Question Number 74141 by MASANJAJ last updated on 19/Nov/19

Commented by TawaTawa last updated on 19/Nov/19

$$\mathrm{d})$$$$\mathrm{a}=5$$$$\mathrm{Forth}\mathrm{term}={\mathrm{ar}}^3=40$$$$\therefore {5\mathrm{r}}^3=40$$$$\therefore {\mathrm{r}}^3=\frac{40}{5}$$$$\therefore {\mathrm{r}}^3=8$$$$\therefore {\mathrm{r}}^3=2^3$$$$\therefore \mathrm{r}=2$$$$\therefore \mathrm{x}=\mathrm{second}\mathrm{term}=\mathrm{ar}=5\times 2=10$$$$\therefore \mathrm{y}=\mathrm{third}\mathrm{term}={\mathrm{ar}}^2=5\times 2^2=5\times 4=20$$

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